(编辑:jimmy 日期: 2024/12/25 浏览:2)
测试时需要大量文件,所以写了脚本进行拷贝。有规律的文件名利于引用。
复制代码 代码如下:
#!/bin/sh
# file name : batchcp.sh
# author: zhouhh
# Email: ablozhou@gmail.com
# Date : 2008.3.31
echo "input your file name"
read FILENAME
echo "how many times you want copy"
read TIMES
echo "your file name is ${FILENAME}, you want to copy ${TIMES} times."
BASE=`echo ${FILENAME}|cut -d "." -f 1`
EXT=`echo ${FILENAME}|cut -d "." -f 2`
for(( i=0;i<${TIMES};i++))
do
echo "copy ${BASE}.${EXT} to ${BASE}$i.${EXT} ..."
cp "${BASE}.${EXT}" "${BASE}$i.${EXT}"
done
另一个版本
复制代码 代码如下:
#!/bin/sh
# file name : batchcp.sh
# author: zhouhh
# Email: ablozhou@gmail.com
# Date : 2008.3.31
echo "input your file name"
read FILENAME
echo "how many times you want copy"
read TIMES
echo "your file name is ${FILENAME}, you want to copy ${TIMES} times."
#find . and cut the left part of the file name using ##
EXT=${FILENAME##*.}
#find . and cut the right part of the file name using %
BASE=${FILENAME%.*}
echo "base:$BASE"
echo "ext:$EXT"
for(( i=0;i<${TIMES};i++))
do
echo "copy ${BASE}.${EXT} to ${BASE}$i.${EXT} ..."
cp "${BASE}.${EXT}" "${BASE}$i.${EXT}"
done